Well you can set
Then solve.
How would you write:
intergral from 2 to infinity of (x+3)/[(x^2-1)(x-1)]
as the limit of a proper intergral, then evaluate the intergral.
Then take the limit to find the improper definite intergral?
The partial fraction is (1/2)ln(x+1) - (1/2)ln(x-1) - 2/(x-1)
thanks
Hello, Ben3535!
What exactly is your question?
It seems that you found the correct partial fractions and you integrated correctly.
So what left?
How would you write: intergral from 2 to infinity of (x+3)/[(x^2-1)(x-1)]
as the limit of a proper intergral, then evaluate the intergral.
Then take the limit to find the improper definite intergral?
The partial fraction is (1/2)ln(x+1) - (1/2)ln(x-1) - 2/(x-1)
Partial fractions: .
Integrate: .
. .
We will evaluate from 2 to
. .
In the first fraction, divide top and bottom by .
. .
. .
. .