First of all, int[(1/2)t^2 dt] = (1/2)(1/3)t^3 = (1/6)t^3, not (1/3)t^3...
This is a differential equation problem, but since I have problem with integration, I am posting here for help. Thank you very much.
I need to integrate the right side
I will list my steps.
1. perform integration by part
2. result
3. again, integration by part
4. result (edited)
The last result is not right. This is the result from the website (Paul's Note)
Pauls Online Notes : Differential Equations - Modeling with First Order DE's (first problem)
I don't even have (200+t)^3
Can someone help me on this? Thank you very much!
It's been a while since I did Calc II, but I do believe that at the end you have Integral (1/2 t ^2 - cos(t) dt)
Someone already pointed out that the inegral of 1/2 t^2 is 1/6 t ^3, but on the second part you have
-2cos(t)*2dt
The integral should be 4sin(t)