1. ## Definite integral

Evaluate each Definite integral.
∫ lower limit 1, upper limit 8. 3-y^(1/3) / y^(2/3) ; dy
I did
∫(3*y^(-2/3) - y^(-1/3)) dy from 1 to 8

9*y^(1/3) - 3/2*y^(2/3) eval. from 1 to 8

= 9(2) - 6 - 9 + 3/2

= 3 + 3/2 = 9/2
Is that right? Thanks

2. I cant really make out properly what the integral is. If you have to integrate 3-(y^1/3)/(y^2/3), the answer will be different. Can you type the problem out properly again. With the proper parentheses?

3. Originally Posted by rowdy3
Evaluate each Definite integral.
∫ lower limit 1, upper limit 8. 3-y^(1/3) / y^(2/3) ; dy
I did
∫(3*y^(-2/3) - y^(-1/3)) dy from 1 to 8

9*y^(1/3) - 3/2*y^(2/3) eval. from 1 to 8

= 9(2) - 6 - 9 + 3/2

= 3 + 3/2 = 9/2
Is that right? Thanks
You can check your answer here: integrate &#40;3 - y&#94;&#40;1&#47;3&#41;&#41;&#47;y&#94;&#40;2&#47; 3&#41; from y &#61; 1 to y &#61; 8 - Wolfram|Alpha

4. Originally Posted by Maanasi
I cant really make out properly what the integral is. If you have to integrate 3-(y^1/3)/(y^2/3), the answer will be different. Can you type the problem out properly again. With the proper parentheses?