Evaluate each Definite integral.
∫ lower limit 1, upper limit 8. 3-y^(1/3) / y^(2/3) ; dy
I did
∫(3*y^(-2/3) - y^(-1/3)) dy from 1 to 8
9*y^(1/3) - 3/2*y^(2/3) eval. from 1 to 8
= 9(2) - 6 - 9 + 3/2
= 3 + 3/2 = 9/2
Is that right? Thanks
Evaluate each Definite integral.
∫ lower limit 1, upper limit 8. 3-y^(1/3) / y^(2/3) ; dy
I did
∫(3*y^(-2/3) - y^(-1/3)) dy from 1 to 8
9*y^(1/3) - 3/2*y^(2/3) eval. from 1 to 8
= 9(2) - 6 - 9 + 3/2
= 3 + 3/2 = 9/2
Is that right? Thanks
You can check your answer here: integrate (3 - y^(1/3))/y^(2/ 3) from y = 1 to y = 8 - Wolfram|Alpha