Thread: Integration substitution.

Use substitution to find each indefinite integral.
∫ 3 du / (square root 3u - 5)
I did
U = 3u -5
dU = 3 du
∫ U^(-1/2)dU =
U^(1/2)/(1/2) + C =
2U^(1/2) + C =
2(3u - 5)^(1/2) + C =
2sqrt(3u - 5)
Is that right?

Thats the right answer. A good trick to double check your primitives is to calculate the derivative of your answer and see if it gives you what you had in the integral.

Originally Posted by rowdy3

Use substitution to find each indefinite integral.
∫ 3 du / (square root 3u - 5)
I did
U = 3u -5
dU = 3 du
∫ U^(-1/2)dU =
U^(1/2)/(1/2) + C =
2U^(1/2) + C =
2(3u - 5)^(1/2) + C =
2sqrt(3u - 5)
Is that right?

+ C!!!