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Math Help - Integration substitution.

  1. #1
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    Integration substitution.

    Use substitution to find each indefinite integral.
    ∫ 3 du / (square root 3u - 5)
    I did
    U = 3u -5
    dU = 3 du
    ∫ U^(-1/2)dU =
    U^(1/2)/(1/2) + C =
    2U^(1/2) + C =
    2(3u - 5)^(1/2) + C =
    2sqrt(3u - 5)
    Is that right?
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  2. #2
    Junior Member RaisinBread's Avatar
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    Thats the right answer. A good trick to double check your primitives is to calculate the derivative of your answer and see if it gives you what you had in the integral.
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  3. #3
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    Quote Originally Posted by rowdy3 View Post
    Use substitution to find each indefinite integral.
    ∫ 3 du / (square root 3u - 5)
    I did
    U = 3u -5
    dU = 3 du
    ∫ U^(-1/2)dU =
    U^(1/2)/(1/2) + C =
    2U^(1/2) + C =
    2(3u - 5)^(1/2) + C =
    2sqrt(3u - 5)
    Is that right?
    + C!!!
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