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Math Help - determine extrema values

  1. #1
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    Question determine extrema values

    (x-1)x^(2/3)
    i found the derivative: which was: (5x/3)^(2/3)-2/(3x^(1/3))
    and the only critical number i could find was: 5x-2=2/5
    and the interval given was [0,1]
    so wuld i jsut use 2/5,0,and 1? are there any more critical numbers?
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  2. #2
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    Quote Originally Posted by menal View Post
    and the only critical number i could find was: 5x-2=2/5
    Is this your solution to solving f'=0?

    If so there is still more work to do.

    The solution to 5x-2=2/5 lies on [0,1], what is it?

    Are there anymore solutions? Have you sketched the function?
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  3. #3
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    would 3/5 be one? (1-(2/5)) and yes that is my solution...and i have graphed the function...my minimum value was correct, but the graph went to positive infinity...so can i still have a maximum?
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