Originally Posted by

**isuckatcalc** yeah, i got that the matrix came out to be 3. is that correct?

alright, so i must be integrating wrong and i still can't figure it out

so bounds of

0<u<1-v

0<v<1

and plugging in the transformations of x=2u +v and y = u +2v into x-3y, i get

2u+v-3u-6v which is -u -5v.

so integrate that with respect to u, i get

-.5u^2 - 5vu.

use the top bound of 1-v, i get

-.5(1-2v+v^2) - (5v-5v^2)

so i multiplied everything by 2 to get rid of the .5. (and i remember there is a 3 outside the integral from the jacobian matrix)