How do I derivate this ln(x^3 +1) thank you
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Originally Posted by Makron How do I derivate this ln(x^3 +1) thank you Use the chain rule. If you need more help I suggest you first review all relevant examples in your class notes and textbook. Then, if you still need more help, please post all your work and say where you get stuck.
Originally Posted by Makron How do I derivate this ln(x^3 +1) thank you You have to use the chain-rule: (Since the LaTeX-compiler doesn't work here the simple calculation f(x)=ln(x^3+1) ==> f'(x)=1/(x^3+1) *d(x^3+1)/dx Simplify the RHS of the equation.
Or to use the simpler notation... Let u = x^3 + 1 so that y = ln(u), and note that dy/dx = (du/dx)(dy/du)
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