Hi.
series: Sigma n from 1 to infinity arctan(n) / n^3/2
I want to determine convergence/divergence.
What i tried:
f(x) = arctan(x) / x^3/2
arctan(x) > f(x)
since arctan(x) converges to pi/2 as x -> inf, f(x) should converge too.
Is that reasoning right?