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**JewelsofHearts** Let *p*(*t*) give the distance in meters from (0, 1) at time *t*.

$\displaystyle

p(t)= <2t,cos(t)>

$

(a) Find the acceleration vector and,

(b) use it to calculate the acceleration at *t* = 5*p*/ 6 .

Explain what the acceleration of the particle means in relation to its position at *t* = 2.

I have differentiated the vectors to get:

v(t)=<2,-sin(t)>

for velocity

and

a(t)<0,-cos(t) >

for acceleration.

-cos(5pi/6)=0.866. Should this be the final answer for acceleration or should the answer be written in vector format? When the problem asks for acceleration, I believe it asking for the net acceleration, so that is why I used the pythagoream theorem to get 0.866.