Hi.
Quick question.
Given a power series of the form:
sigma cn(x+3)^n. It is given that this series converges when x=0 and diverges when
x = -8
Now does it converge when the series is
sigma cn2^n
The answer is yes but not sure how to justify.
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Hi.
Quick question.
Given a power series of the form:
sigma cn(x+3)^n. It is given that this series converges when x=0 and diverges when
x = -8
Now does it converge when the series is
sigma cn2^n
The answer is yes but not sure how to justify.
Hint:
Asconverges, the radius of convergence of the series
is
I was trying to figure out the radius of convergence. This is what i have.Quote:
Originally Posted by FernandoRevilla
Hint:
As
we know that |z-a| < R means that the series converges absolutely for some number R.
Here i have a as (-3) and z=x=0 when it converges.
so |-3| < R => |3| < R
now |3| can be + or - 3...so I guess is R > -3 or 3?
I dunno if im doing this right.