I need to calculate the limit of (1/3^(n+2)-1/5^(n+2))/(1/3^(n+1)-1/5^(n+1)) where n tends to infinity, i know the answer is 1/3 but I don't understand how you get that.

Can anyone explain? I will be grateful for any help.

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- April 10th 2011, 05:48 PMjoesmithcalculating a limit
I need to calculate the limit of (1/3^(n+2)-1/5^(n+2))/(1/3^(n+1)-1/5^(n+1)) where n tends to infinity, i know the answer is 1/3 but I don't understand how you get that.

Can anyone explain? I will be grateful for any help. - April 10th 2011, 06:17 PMtopsquark
- April 10th 2011, 06:37 PMjoesmith
Thanks i've just figured it out