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Math Help - Finding derivative of a Exponential Function

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    Finding derivative of a Exponential Function

    y=(e^(8x))/(2x^(2)-3)
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    Quote Originally Posted by wallyg View Post
    y=(e^(8x))/(2x^(2)-3)
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    This is a job for the quotient rule.

    If \displaystyle y=\frac{u}{v} \implies y'=\frac{vu'-uv'}{v^2}

    Also \displaystyle y=e^{8x} \implies y'=8e^{8x}
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    Would the answer be (2x-3)*(8e^(8x)-e^(8x)*2)/(2x^(2)-3)^(2) ?
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    Quote Originally Posted by wallyg View Post
    Would the answer be (2x-3)*(8e^(8x)-e^(8x)*2)/(2x^(2)-3)^(2) ?
    I don't think so, given your function is \displaystyle \frac{e^{8x}}{2x^2-3} then

    \displaystyle \left(\frac{e^{8x}}{2x^2-3}\right)' = \frac{(2x^2-3)(e^{8x})'-e^{8x}(2x^2-3)'}{(2x^2-3)^2}
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