$\displaystyle I = \displaystyle 3 \int_0^{2} \frac{1}{\sqrt{2-x}} dx$

$\displaystyle I = \displaystyle -6\sqrt{2-x} \right]_0^{2} $

$\displaystyle I = \displaystyle -6\sqrt{0} + 6\sqrt{2} $

$\displaystyle I = \displaystyle 6\sqrt{2} $

is this correct

OR

$\displaystyle \displaystyle \lim_{\epsilon \to 2}\left[ -6\sqrt{2-\epsilon} \right]_0^{\epsilon} $