# Math Help - EValuate this indefinite integral?

1. ## EValuate this indefinite integral?

$I = \displaystyle \int_{}{} \frac{dx}{x\sqrt{1-(In x)^2}}$

help

2. Let $u = \ln{x}$ and it becomes $\int\frac{1}{\sqrt{1-u^2}}\;{du}$ (a standard integral).

3. Originally Posted by Hardwork
Let $u = \ln{x}$ and it becomes $\int\frac{1}{\sqrt{1-u^2}}\;{du}$ (a standard integral).
thanks, I feel stupid for missing how obvious it is