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Math Help - EValuate this indefinite integral?

  1. #1
    Junior Member bijosn's Avatar
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    EValuate this indefinite integral?

    I = \displaystyle \int_{}{} \frac{dx}{x\sqrt{1-(In x)^2}}

    help
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  2. #2
    Junior Member Hardwork's Avatar
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    Let u = \ln{x} and it becomes \int\frac{1}{\sqrt{1-u^2}}\;{du} (a standard integral).
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  3. #3
    Junior Member bijosn's Avatar
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    Quote Originally Posted by Hardwork View Post
    Let u = \ln{x} and it becomes \int\frac{1}{\sqrt{1-u^2}}\;{du} (a standard integral).
    thanks, I feel stupid for missing how obvious it is
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