# EValuate this indefinite integral?

• Apr 9th 2011, 03:27 AM
bijosn
EValuate this indefinite integral?
$I = \displaystyle \int_{}{} \frac{dx}{x\sqrt{1-(In x)^2}}$

help
• Apr 9th 2011, 03:36 AM
Hardwork
Let $u = \ln{x}$ and it becomes $\int\frac{1}{\sqrt{1-u^2}}\;{du}$ (a standard integral).
• Apr 9th 2011, 03:46 AM
bijosn
Quote:

Originally Posted by Hardwork
Let $u = \ln{x}$ and it becomes $\int\frac{1}{\sqrt{1-u^2}}\;{du}$ (a standard integral).

thanks, I feel stupid for missing how obvious it is