I'm having trouble getting:
ln(x/y)=(e^-x)(cos(y/2))
down to where I can separate y'. I was able to get it down to:
(1/x)-(1/y)(y')=e^-x (sin(y/2)(y'/2))
d/dx cos(y/2)= -sin(y/2)(y'/2) correct?
Wow thank you, can't believe I forgot to apply the product rule...
actually I got this the first time I tried the problem, but the problem with doing it this way is when I get all the y' on one side there doesn't seem a way to take out the y'.
((2/y')-(y'/y))=(((-e^-x)(cos(y/2)))-(e^-x)(sin(y/2)-(1/x))
((2y-(y'^2))/(y'(y)))=...