Thread: integral of cos squared x sin x - substition guidance required

Hi

I know that the answer to integral of cos^2 x sin x dx is -cos^3/3 but I am having trouble figuring out how the prof got there.

Do you substitute u = cos x so du = -sin x? or do you substitute u = cos^2 x but then I am not sure what du =.

Any guidance would be greatly appreciated.

Thanks

In this case, you would do with What does

become?

it becomes integral -u^2 du which is -u^3/3 and then substitute back the cos x.

Thank you very very very much. I just wasn't seeing before.

Don't forget your constant of integration if it's an indefinite integral

That's right. You're welcome!

P.S. Don't forget the constant of integration. Very important!