explicitdifferentiation? I'd like to see how you pulled that off w/o an algebraic mess. You sure you don't meanimplicitdifferentiation?

no matter ... sub x = 1 into the original equation for the curve to find its corresponding y-value (note there is only one solution in this case). use the x=1 and its corresponding y-value to determine the value of the derivative at that point. finally, write the tangent line equation.