Solve this!!

∞∑n=0 (sin2nө/n!)

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- August 10th 2007, 06:05 AMkamaksh_icefourier
**Solve this!!**

**∞∑n=0 (sin2nө/n!)** - August 10th 2007, 06:24 AMtopsquark
I'm very rusty on this, but assume we have a function such that the Fourier sine series for f is

Then we need to invert the Fourier sine series, which if I remember correctly means that

Someone needs to check me on that result, but it's going to be something of the sort. (The best way for you, kamaksh_ice, to check me is to do the problem then take the Fourier sine series of the result and see if you get your original series back.)

-Dan