Thread: Locate relative extrema is this working correct?

Locate and describe the relative extrema then sketch the graph of



is the theory correct?

review your algebra ...

After , you wrote , which is false. Expand the left-hand side of the false equation to see why.

Instead, divide the equation by :



Then, factor the right-hand side of the equation:



Set each factor on the right-hand side of the equation equal to 0.

or

Solve each equation in terms of x. The solutions are the critical values.

Originally Posted by NOX Andrew

After , you wrote , which is false. Expand the left-hand side of the false equation to see why.

Instead, divide the equation by :



Then, factor the right-hand side of the equation:



Set each factor on the right-hand side of the equation equal to 0.

or

Solve each equation in terms of x. The solutions are the critical values.

so x=1 or x =-3

what do i do with the 3 outside the brackets? 3x = 0 ?

No, only set factors with an equal to 0. In other words, don't multiply a constant by an and then set the product equal to 0. If you really wanted to, you could set just equal to . However, is false, so there are no solutions to that specific equation.