laplace{tsin2t}
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Originally Posted by alderon laplace{tsin2t} $\displaystyle \mathcal{L}\{t \sin(2t) \}= -\frac{d}{ds} \mathcal{L} \{\sin(2t) \} $$\displaystyle =\frac{d}{ds}~\left[ \frac{-2}{s^2+4} \right]$ RonL
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