how do i do the last bit? im unsure with the "2" root x do i put 1 over 2 root x out in front of 2 and minus 1 from 2 root x at the end. i dont know how to write this or if its correct
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First, note $\displaystyle \displaystyle -3 \cdot -8 =+24$
oh yeah sorry missed the 2 negatives
What's the derivative of $\displaystyle \displaystyle 2x^{\frac{1}{2}}$?
2.5 over root x?
Half of 2 is not 2 and a half...
The two alternatives you gave appear to be equivalent. $\displaystyle \displaystyle \frac{1}{x^{\frac{1}{2}}} = \frac{1}{\sqrt{x}}$ Both are correct.
is this the correct answer thanks for all help
its right
Except that you wrote two different things for y'. The first, $\displaystyle y'= 24x^{-9}+ 2x^{1/2}$, is wrong because you haven't yet differentiated the second term.