1. ## quotient rule

2. $\displaystyle y= \frac{3}{5r+11}\implies y' = \frac{(5r+11)\times (3)'-(5r+11)'(3)}{(5r+11)^2}$

3. thanks for the answer could you please explain the steps reasoning so i can get it.

4. Yep, I can,

The quotient rule

$\displaystyle y= \frac{u}{v}\implies y' = \frac{vu'-v'u}{v^2}$

Or you can say

$\displaystyle y= \frac{3}{5r+11} = 3(5r+11)^{-1}$

then use the chain rule.

5. thank you very much i now see how you did it thanks a bunch

6. By the way, seeing as this is clearly a Calculus question, why have you posted it in Pre-Calculus?

7. I thought only university questions could go there?

if that's wrong how do i move the thread?

8. To move the thread, report your own post using the Report Post tool at the lower left corner of the OP. Looks like a triangle with an exclamation mark inside it. A mod will move it for you.