Find g'(x) by using Part 2 of the Fundamental Theorem of Calculus.

$\displaystyle g(x) = \int^x_0 (1+\sqrt{t})dt$

Here is what I have done so far:

$\displaystyle g(x) = t + \frac{1}{2\sqrt{t}}]^x_0$

$\displaystyle g(x) = x + \frac{1}{2\sqrt{x}} - (0 + \frac{1}{2\sqrt{0}})$

Assuming that these two steps are correct (are they?), how do handle the fact that $\displaystyle \frac{1}{2\sqrt{0}}$ is undefined?

Thanks!