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Math Help - calculus

  1. #1
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    calculus

    but in the answer they told that y^2=x-1 is not a function.there are several example in other books like this one.according to the other book it is not a function
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    Quote Originally Posted by Mohsin View Post
    but in the answer they told that y^2=x-1 is not a function.there are several example in other books like this one.according to the other book it is not a function
    You've already been asked to continue this conversation in the original thread. It is too confusing to post new information without the original.

    Please stop this NOW.

    If you are having trouble finding the original post, simply ask.

    -Dan
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  3. #3
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    Quote Originally Posted by Mohsin View Post
    but in the answer they told that y^2=x-1 is not a function.there are several example in other books like this one.according to the other book it is not a function
    Let me add more to your confusion.

    y^2 = x -1
    "is not a function" if you mean y as a function of x.
    It is the square of y, where y is a function of x.

    y = f(x) = sqrt[x-1] ------the positive root of the square root only.
    If you include the negative root, then y is not f(x) anymore. Because y will have two values for every x-value in the domain.

    Domain? Please don't ask me on that.

    If that confuses you more, same here.

    Heck, who invented functions? And who approved the invention? Those guys can be sued in court.
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