but in the answer they told that y^2=x-1 is not a function.there are several example in other books like this one.according to the other book it is not a function

Printable View

- Aug 9th 2007, 12:30 PMMohsincalculus
but in the answer they told that y^2=x-1 is not a function.there are several example in other books like this one.according to the other book it is not a function

- Aug 9th 2007, 12:49 PMtopsquark
- Aug 9th 2007, 12:52 PMticbol
Let me add more to your confusion.

y^2 = x -1

"is not a function" if you mean y as a function of x.

It is the square of y, where y is a function of x.

y = f(x) = sqrt[x-1] ------the positive root of the square root only.

If you include the negative root, then y is not f(x) anymore. Because y will have two values for every x-value in the domain.

Domain? Please don't ask me on that.

If that confuses you more, same here.

Heck, who invented functions? And who approved the invention? Those guys can be sued in court.