How do you integrate (x-1)/sqrt(x)? Thanks.
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Originally Posted by Savior_Self How do you integrate (x-1)/sqrt(x)? Thanks. Hint: $\displaystyle \displaystyle \frac{x-1}{\sqrt{x}}=x^{\frac{1}{2}}-x^\frac{-1}{2}$ Now use the power rule!
wait, how does $\displaystyle \frac{x-1}{\sqrt{x}} = x^{1/2} - x^{-1/2}$? I get that it equals $\displaystyle (x-1)(x^{-1/2})$... I just don't see the steps you took to get past that.
Originally Posted by Savior_Self wait, how does $\displaystyle \frac{x-1}{\sqrt{x}} = x^{1/2} - x^{-1/2}$? I get that it equals $\displaystyle (x-1)(x^{-1/2})$... I just don't see the steps you took to get past that. Expand the brackets, using the rule that $\displaystyle (x^a)(x^b)=x^{a+b}$
Thanks. So the answer is: $\displaystyle \frac{2x^{3/2}}{3}-2x^{1/2}+C$ correct?
Originally Posted by Savior_Self Thanks. So the answer is: $\displaystyle \frac{2x^{3/2}}{3}-2x^{1/2}+C$ correct? yes you can check by taking the derivative!
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