y = 2 - xe^x I got: = d(2) + d(-x)(e^x) + d(e^x)(-x) dx dx dx = 0 + (1)(e^x) + (e^x)(-x) = e^x - xe^x = e^x (x-1) But I don't know if I am correct? Appreciate all help, thanks in advanced!
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= d(2) + d(-x)(e^x) + d(e^x)(-x) dx dx dx = 0 + (1)(e^x) + (e^x)(-x) I think you dropped a minus sign $\displaystyle \frac{d(-x)}{dx} = -1$ So line 2 would read = 0 + (-1)(e^x) + (e^x)(-x)
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