# Math Help - alternating series help

1. ## alternating series help

can anyone verify by b_n for these series...thx!

sin(2n-1)(pi) / 2 b_n = pi/2

cosn(pi) b_n = (pi)

cos(n[pi]) / sqrt(n) b_n = 1 / sqrt(n)

cosn(pi) / (n+1) b_n = (pi) / (n+1)

nosn(pi) / n² b_n = 1/n²

2. Originally Posted by lochnessmonster
can anyone verify by b_n for these series...thx!

sin(2n-1)(pi) / 2 b_n = pi/2

cosn(pi) b_n = (pi)

cos(n[pi]) / sqrt(n) b_n = 1 / sqrt(n)

cosn(pi) / (n+1) b_n = (pi) / (n+1)

nosn(pi) / n² b_n = 1/n²

Perhaps it's only me, but I don't have the slightest idea what you want..."verify by b_n"??

It'd help if you show some self work, too.

Tonio

3. Also, it would help if you would at least make your equations readable...

The first one for example, I can't tell if it's $\displaystyle \frac{\sin^{2n-1}\pi}{2}b_n$, $\displaystyle \frac{\sin{[(2n-1)\pi]}}{2}b_n$, $\displaystyle \frac{\sin^{2n-1}{\pi}}{2b_n}$ or $\displaystyle \frac{\sin{[2(n-1)\pi]}}{2b_n}$...