Thread: alternating series help

can anyone verify by b_n for these series...thx!

sin(2n-1)(pi) / 2 b_n = pi/2



cosn(pi) b_n = (pi)



cos(n[pi]) / sqrt(n) b_n = 1 / sqrt(n)




cosn(pi) / (n+1) b_n = (pi) / (n+1)


nosn(pi) / n² b_n = 1/n²

Originally Posted by lochnessmonster

can anyone verify by b_n for these series...thx!

sin(2n-1)(pi) / 2 b_n = pi/2



cosn(pi) b_n = (pi)



cos(n[pi]) / sqrt(n) b_n = 1 / sqrt(n)




cosn(pi) / (n+1) b_n = (pi) / (n+1)


nosn(pi) / n² b_n = 1/n²

Perhaps it's only me, but I don't have the slightest idea what you want..."verify by b_n"??

It'd help if you show some self work, too.

Tonio

Also, it would help if you would at least make your equations readable...

The first one for example, I can't tell if it's , , or ...