can anyone verify by b_n for these series...thx! sin(2n-1)(pi) / 2 b_n = pi/2 cosn(pi) b_n = (pi) cos(n[pi]) / sqrt(n) b_n = 1 / sqrt(n) cosn(pi) / (n+1) b_n = (pi) / (n+1) nosn(pi) / nē b_n = 1/nē
Follow Math Help Forum on Facebook and Google+
Originally Posted by lochnessmonster can anyone verify by b_n for these series...thx! sin(2n-1)(pi) / 2 b_n = pi/2 cosn(pi) b_n = (pi) cos(n[pi]) / sqrt(n) b_n = 1 / sqrt(n) cosn(pi) / (n+1) b_n = (pi) / (n+1) nosn(pi) / nē b_n = 1/nē Perhaps it's only me, but I don't have the slightest idea what you want..."verify by b_n"?? It'd help if you show some self work, too. Tonio
Also, it would help if you would at least make your equations readable... The first one for example, I can't tell if it's , , or ...
View Tag Cloud