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Math Help - alternating series help

  1. #1
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    alternating series help

    can anyone verify by b_n for these series...thx!

    sin(2n-1)(pi) / 2 b_n = pi/2



    cosn(pi) b_n = (pi)



    cos(n[pi]) / sqrt(n) b_n = 1 / sqrt(n)




    cosn(pi) / (n+1) b_n = (pi) / (n+1)


    nosn(pi) / nē b_n = 1/nē
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  2. #2
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    Quote Originally Posted by lochnessmonster View Post
    can anyone verify by b_n for these series...thx!

    sin(2n-1)(pi) / 2 b_n = pi/2



    cosn(pi) b_n = (pi)



    cos(n[pi]) / sqrt(n) b_n = 1 / sqrt(n)




    cosn(pi) / (n+1) b_n = (pi) / (n+1)


    nosn(pi) / nē b_n = 1/nē


    Perhaps it's only me, but I don't have the slightest idea what you want..."verify by b_n"??

    It'd help if you show some self work, too.

    Tonio
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  3. #3
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    Also, it would help if you would at least make your equations readable...

    The first one for example, I can't tell if it's \displaystyle \frac{\sin^{2n-1}\pi}{2}b_n, \displaystyle \frac{\sin{[(2n-1)\pi]}}{2}b_n, \displaystyle \frac{\sin^{2n-1}{\pi}}{2b_n} or \displaystyle \frac{\sin{[2(n-1)\pi]}}{2b_n}...
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