Find the absolute extrema if they exist as well as all values of x where they occur, for each function and specified domain.

F(x)= (1-x) / (3+x) ; [0,3]

I did the quotient rule. u= 1-x and u'= 1 and v= 3+x and v'= 1

F'(x)= (3+x)(1) - (1-x)(1) / (3+x)^2

F'(x)= 3+x-1+x / (3+x)^2

F'(x)= 2+2x / (3+x)^2

Would I take out a 2 on top? I need to set it to zero but how do I do that?

0= x/(3+x)^2

The bottom is -3 and undefined. So the only numbers I have to do is 0 and 3. I plug it into the original problem and (0, 1/3) and (3, -1/3). 1/3 is absolute max and -1/3 is absolute min.