I'm working from a book and trying to integrate $\displaystyle \sqrt[4]{2x^{3}}$, unfortunately I always arrive at the wrong answer. Can anyone point out where I'm going wrong with this working?

$\displaystyle \sqrt[4]{2x^{3}}=(2x)^\frac{3}{4}$

Therefore

$\displaystyle \frac{dy}{dx}=\frac{3}{4}(2x)^\frac{-1}{4}=\frac{3}{4}(\frac{1}{\sqrt[4]{2x}})$