What value(s) of c is (are) predicted by the Mean Value Theorem for f (x) = (x − 2)^3 on the interval [0, 2]?

this is my attempt but its wrong I think

$\displaystyle \frac{(x-2)^4}{4}\big|_0^2$

$\displaystyle = 0 - \frac{16}{4} $

$\displaystyle = -4 $

$\displaystyle f(c)(b-a) = -4 $

$\displaystyle (c -2)^3(2 -0) = -4 $

$\displaystyle (c -2)^3 = -2 $

$\displaystyle (c -2) = (-2)^{\frac{1}{3}} $

$\displaystyle c = (-2)^{\frac{1}{3}} + 2 $