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Math Help - Inverse Laplace Transform

  1. #1
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    Inverse Laplace Transform

    I have no idea how to solve the problem with the inverse laplace transforms.

    *Find the Inverse laplace transform of { 3/ (s + 4) }

    I guessed that the answer, f(t) would be: 3 cos 2t


    However it doesn't make sense because according to the table, -cos kt- is equal to F(s)=> s / (s^(2) + k^(2)).

    In this case, s is not squared. I am not sure about k because I think it's not squared. If it is squared then k is equal to 2. That's how I got
    3 cos 2t.

    however if k is not squared then k is equal to 4. I am confused...

    Please help
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  2. #2
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    The inverse LaPlace of \frac{3}{s+4}=3e^{-4t}

    e^{-at}=\frac{1}{s+a}
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