find y'

I began this by

letting

the answer I get is

which is wrong

- Mar 26th 2011, 02:22 AMbijosnIf [tex]y = In \left[ \frac{x(x^2 + 1)}{\sqrt{x^3 - 1}} \right] [/tex]
find y'

I began this by

letting

the answer I get is

which is wrong - Mar 26th 2011, 02:28 AMProve It
What are you trying to do? Differentiate this function?

.

Go from here... - Mar 26th 2011, 02:33 AMbijosn
- Mar 26th 2011, 06:43 AMbijosn
.

I am a bit lost and rusty, I could do this a month back but now I've forgotten what to do.

the right hand side looks like this

what do I do now