so i have calculated R=+or-1/6, and when R=1/6, the series reduced to , now how do we test if this series convergent or not?

The second one

for this one, I have got R=+or- 9/7, and the series reduced to , what is the next step?

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- Mar 25th 2011, 08:09 PMwopashuiinvestigate the convergence at the radius of convergence

so i have calculated R=+or-1/6, and when R=1/6, the series reduced to , now how do we test if this series convergent or not?

The second one

for this one, I have got R=+or- 9/7, and the series reduced to , what is the next step? - Mar 25th 2011, 10:02 PMmatheagle
how did you get R=1/6?

I thought it was 1/2 as well, but I did this really quick.

I wanted to see the poster's work. - Mar 25th 2011, 10:19 PMProve It
1. Your series is .

Using the ratio test

.

The series is convergent when this limit . So

.

So the radius of convergence is , not ...

Now substitute each of the endpoints of this interval of convergence into your original series, and test the convergence of those series... - Mar 26th 2011, 10:54 AMwopashui
- Mar 26th 2011, 07:38 PMProve It
Absolutely not! The changing terms will change the value of the series.

The whole point in using the ratio test is to find the values of for which the series is going to converge. If you leave them out, then you're only determining the convergence of the series when . - Mar 27th 2011, 12:31 PMwopashui
- Mar 27th 2011, 07:30 PMProve It
You're not listening to me.

The is part of . If you're going to use the ratio test, then you need to use ALL of and . In fact, the term is the most important part, because when you have evaluated what is, you will get an expression for . THIS IS THE IMPORTANT PART, because you know that the series will converge when this limit is , which means you can solve to find the values of for which the series will converge. THIS abosolute value is the radius of convergence, and the resulting interval is the interval of convergence. - Mar 27th 2011, 08:42 PMmatheagle
i am so listening

but I'm busy grading exams