Can anyone help me with this cos(^2)x.(dy/dx) +y = tanx i followed the general way but i can't integrate tanxsec^2x.e^tanx thanks
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Originally Posted by Dili Can anyone help me with this cos(^2)x.(dy/dx) +y = tanx i followed the general way but i can't integrate tanxsec^2x.e^tanx thanks Let tanx=u, then integrate (ue^u)du
Originally Posted by Dili i followed the general way but i can't integrate tanxsec^2x.e^tanx Add & subtract $\displaystyle e^{\tan{x}}\cdot\sec^2x$ Then group some terms to turn the integrand into a product's function derivative. The general solution to your differential equation is $\displaystyle \color{blue}y=k\cdot{e}^{-\tan{x}}+\tan{x}-1,~~k\in\mathbb{R}$
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