The question is:

$\displaystyle y= (lntanx)^2$

I did:

$\displaystyle

y'= 2(lntanx) * [ \frac{1}{x} + lnsec^2x]$

Out of all that I've done it seems like it's more along the easy side, but you can never be too sure. Just want to double check my work. Thanks.