Say we have that f(1)=3, f '(1)=3, g(1)=2, g '(1)=2 and also f(3)=6, f '(3)=1, g(3)=1, g '(3)=0

I found that (f/g)'(1)=0.

What can you assert about (f/g)'(3)?

Is there enough information to calculate f ''(3)?

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- March 23rd 2011, 03:53 PMsteph3824Algebraic rules for derivatives
Say we have that f(1)=3, f '(1)=3, g(1)=2, g '(1)=2 and also f(3)=6, f '(3)=1, g(3)=1, g '(3)=0

I found that (f/g)'(1)=0.

What can you assert about (f/g)'(3)?

Is there enough information to calculate f ''(3)?