$\displaystyle \frac{e^t-1}{t}$
I know this is a simple derivative, and I'm in calc 3, but I can't seem to figure this one out....
Okay, well that's really small. It's e^t-1/t in case you can't see it.
Have you tried using the quotient rule?
Let $\displaystyle f(t)=e^t-1$
Then, $\displaystyle f'(t)=e^t$
Let $\displaystyle g(t)=t$
$\displaystyle g'(t)=1$
The rule states that:
For any function composed of a quotient of two other functions, here denoted by $\displaystyle \displaystyle\frac{f(t)}{g(t)}$, the derivative is:$\displaystyle \displaystyle\frac{f'(t)g(t)-g'(t)f(t)}{[g(t)]^2}$
...So do the substitution.
If you haven't covered the quotient rule, then reply and I'll try another approach