I hope its ok I put it as an attachment- I'm really slow/bad at typing in TEX... but basically I got stuck where I integrate 1/sec^2theta...I feel like something went wrong when I got this...
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Originally Posted by bcahmel I hope its ok I put it as an attachment- I'm really slow/bad at typing in TEX... but basically I got stuck where I integrate 1/sec^2theta...I feel like something went wrong when I got this... You are fine! You just need to draw a right triangle. From the above diagram you can see that $\displaystyle \displaystyle \sin(\theta)=\frac{x}{\sqrt{x^2+16}}$ and $\displaystyle \displaystyle \cos(\theta)=\frac{4}{\sqrt{x^2+16}}$ Now just sub all of this in
thank you! I was convinced i had it wrong...but there are so many steps to these problems.
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