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Math Help - trigonometric substitution-another problem

  1. #1
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    trigonometric substitution-another problem

    trigonometric substitution-another problem-mathprobcalc.jpg

    I hope its ok I put it as an attachment- I'm really slow/bad at typing in TEX...

    but basically I got stuck where I integrate 1/sec^2theta...I feel like something went wrong when I got this...
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by bcahmel View Post
    Click image for larger version. 

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    I hope its ok I put it as an attachment- I'm really slow/bad at typing in TEX...

    but basically I got stuck where I integrate 1/sec^2theta...I feel like something went wrong when I got this...
    You are fine! You just need to draw a right triangle.

    trigonometric substitution-another problem-capture.jpg



    From the above diagram you can see that

    \displaystyle \sin(\theta)=\frac{x}{\sqrt{x^2+16}} and
    \displaystyle \cos(\theta)=\frac{4}{\sqrt{x^2+16}}

    Now just sub all of this in
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  3. #3
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    thank you! I was convinced i had it wrong...but there are so many steps to these problems.
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