Attachment 21233

I hope its ok I put it as an attachment- I'm really slow/bad at typing in TEX...

but basically I got stuck where I integrate 1/sec^2theta...I feel like something went wrong when I got this...

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- Mar 23rd 2011, 08:06 AMbcahmeltrigonometric substitution-another problem
Attachment 21233

I hope its ok I put it as an attachment- I'm really slow/bad at typing in TEX...

but basically I got stuck where I integrate 1/sec^2theta...I feel like something went wrong when I got this... - Mar 23rd 2011, 08:15 AMTheEmptySet
You are fine! You just need to draw a right triangle.

Attachment 21234

http://www.mathhelpforum.com/math-he...2&d=1300896836

From the above diagram you can see that

$\displaystyle \displaystyle \sin(\theta)=\frac{x}{\sqrt{x^2+16}}$ and

$\displaystyle \displaystyle \cos(\theta)=\frac{4}{\sqrt{x^2+16}}$

Now just sub all of this in - Mar 23rd 2011, 08:21 AMbcahmel
thank you! :) I was convinced i had it wrong...but there are so many steps to these problems.