Hi, I was wondering if you could help me out with a few problems

1)log (3x+8x^3)

2)3sqrr(2x-1)

3)e^x.cosecx

4)e^(4x+3)/4x+3

5)find g'''(x) when g(x)=7x^3-2x^2+4x-8

6)If x=sin(x) y= sec(x) find dy/dx

7)x=t^2 y=2t + 1

find the equation of the tangent at the point where t=2

I ended up with

1)24x^2 + 3/3x+8x^3

2)2/3(2x-1)^-2/3

3)-cosecxcotx.e^x + cosec.e^x

4)4e^4x+3(4x+3)-4e^4x+3/(4x+3)^2

5)42

6)sec(x).tan(x)/cos(x)

7)1/2x + 3

are my answers correct?

Thanks in advance