How do I find the first partials of the function below? $\displaystyle f(x,y)=\int_{y}^{x}cos(t^{2})dt$
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Originally Posted by bilalsaeedkhan How do I find the first partials of the function below? $\displaystyle f(x,y)=\int_{y}^{x}cos(t^{2})dt$ You need to use the fundamental theorem of calculus. $\displaystyle \displaystyle \frac{\partial f}{\partial y}=\frac{\partial }{\partial y}\left(-\int_{x}^{y}cos(t^{2})dt\right) =-\cos(y^2)$ now try the x one.
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