let dv = x^2 v = x^3/3 let u = sin^-1{x} for the 2nd integral: integrat and my answer wud be: but the answer at the back of book is:
Follow Math Help Forum on Facebook and Google+
Originally Posted by ^_^Engineer_Adam^_^ let dv = x^2 v = x^3/3 let u = sin^-1{x} ...... for the 2nd integral For the 2nd integral let x=sint.
using trigo sub i will get a value of how do i simplify to get the corect answer?
Originally Posted by ^_^Engineer_Adam^_^ For the second one set
Originally Posted by ^_^Engineer_Adam^_^ using trigo sub i will get a value of how do i simplify to get the corect answer? The correct answer is where
View Tag Cloud