let dv = x^2

v = x^3/3

let u = sin^-1{x}

for the 2nd integral:

integrat

and my answer wud be:

but the answer at the back of book is:

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- Aug 5th 2007, 10:27 PM^_^Engineer_Adam^_^int x^2sin^-1(x)

let dv = x^2

v = x^3/3

let u = sin^-1{x}

for the 2nd integral:

integrat

and my answer wud be:

but the answer at the back of book is:

- Aug 5th 2007, 11:18 PMcurvature
- Aug 6th 2007, 03:38 AM^_^Engineer_Adam^_^
using trigo sub

i will get a value of

how do i simplify to get the corect answer? - Aug 6th 2007, 10:17 AMKrizalid
- Aug 6th 2007, 10:00 PMcurvature