A rectangular garden laid out along a neighbour's lot contains 432 m^2. It is to be fenced on all sides. If the neighbour pays for half the shared fence, what should be the dimensions of the garden so that your cost is a minimum??
This is area = A'=0 is the derivative/
So A = l x w...........................so notes on the side is w x l = 432.
Where I am stuck is that do I take half of L and half of W for the equation??
So I use A = l/2 X w/2??
Answer is 18 x 24 m.