Hi can you just check that I have this integration correct?
(1 - r^2/R)
Solution
( r - r^3/3)
Cheers!
Sorry Ill explain myself better. The question relates to charge distribution that is spherically symmetrical. This charge distribution is over the range:
A(1 - r/R) for r< R
and
0 for r > R
Where A is a constant
Making a few assumptions about the charge distribution we get:
Q = A( 1 - r/R) × 4πr^2* δr = 4πA(1 - r^3/R)δr
π = pi
So to find the total charge over the whole of sphere we take integral from R to 0:
Q = 4πA(1 - r^3/R) = 4πA [This is the bit i am obviously getting wrong!] = ??????
Sorry about using the correct symbols but i don't seem to be able to cut and paste from word into the forum