$\displaystyle

dx/dt=1/(t+1) dy/dt=2t

$

Write an equation expressing y in terms of x.

So far, I have $\displaystyle x=ln(t+1)+C$ and $\displaystyle y=t^2+C$

So,

t=e^(x-C)-1

and y would equal:

y=(e^(x-C)-1)^2+D

I don't know how to get rid of the 'Cs' or if the 'D' should be a C. I thought that there should be a D because the D represnts the constant from the y equation.

Not really sure if I'm doing this problem properly.