I would use the chain rule to get and find y from there
Write an equation expressing y in terms of x.
So far, I have and
So,
t=e^(x-C)-1
and y would equal:
y=(e^(x-C)-1)^2+D
I don't know how to get rid of the 'Cs' or if the 'D' should be a C. I thought that there should be a D because the D represnts the constant from the y equation.
Not really sure if I'm doing this problem properly.