the function is
3x(2-3x^2)^-1/2
so as im finding the derivative i get the first line as
3x((-1/2)(2-3x^2))^((-3/2))(-6x)+(2-3x^2)^(-1/2)(3))
is this right so far?
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the function is
3x(2-3x^2)^-1/2
so as im finding the derivative i get the first line as
3x((-1/2)(2-3x^2))^((-3/2))(-6x)+(2-3x^2)^(-1/2)(3))
is this right so far?
Yes.