the function is

3x(2-3x^2)^-1/2

so as im finding the derivative i get the first line as

3x((-1/2)(2-3x^2))^((-3/2))(-6x)+(2-3x^2)^(-1/2)(3))

is this right so far?

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- Mar 19th 2011, 04:33 AMnando29finding derivative using chain and product rule
the function is

3x(2-3x^2)^-1/2

so as im finding the derivative i get the first line as

3x((-1/2)(2-3x^2))^((-3/2))(-6x)+(2-3x^2)^(-1/2)(3))

is this right so far? - Mar 19th 2011, 04:50 AMAlso sprach Zarathustra
Yes.