For each curve, find the equation of the tangent at the given point.
a) x^2 + y^2 = 13 at (2, -3)
I got the slope, which is - x/y but I have no clue how to put this into an equation.
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Use point-slope form:
I have tried that. I get y=2/3 (x) + 5/3 (correct me if I'm wrong), but the answer in the back of my textbook is 2x - 3y - 13 = 0
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